432=12n^2

Solution for 432=12n^2 equation:

432=12n^2

We move all terms to the left:

432-(12n^2)=0

a = -12; b = 0; c = +432;
Δ = b2-4ac
Δ = 02-4·(-12)·432
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144}{2*-12}=\frac{-144}{-24}
=+6
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144}{2*-12}=\frac{144}{-24}
=-6
$